
Are you ready to take your first step toward achieving your goal?
- 10 diagnosis quiz questions
- 10 minutes in duration
- Required to attempt all questions
- A mixture of short answer and multiple-choice questions
- Instant feedback straight after the test
OK, let’s get started now!

Are you ready to take your first step toward achieving your goal?
- Ten diagnosis quiz questions
- Ten minutes in duration
- Required to attempt all questions
- A mixture of short-answer and multiple-choice questions
- Instant feedback straight after the quiz
OK, let’s get started now!
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- Incorrect
- Question 1 of 10
1. Question
Find \(x\), \(y\) and \(z\) if \(\left( {\begin{array}{*{20}{c}}
{x – 3}\\
{y + 2}\\
{z + 4}
\end{array}} \right) = \left( {\begin{array}{*{20}{c}}
1\\
3\\
{ – 2}
\end{array}} \right)\)\(x = \) , \(y = \) , \(z = \)
CorrectIncorrect - Question 2 of 10
2. Question
Find scalars \(a\), \(b\) and \(c\), if \(2\left( {\begin{array}{*{20}{c}}
1\\
2\\
{c + 1}
\end{array}} \right) = \left( {\begin{array}{*{20}{c}}
{a – 1}\\
b\\
6
\end{array}} \right)\).\(a = \) , \(b = \) , \(c = \)
CorrectIncorrect - Question 3 of 10
3. Question
Find \(k\), correcting to two significant figures, such a vector \(k\left( {\begin{array}{*{20}{c}}
2\\
{ – 3}\\
2
\end{array}} \right)\) is in the same direction as \(\left( {\begin{array}{*{20}{c}}
2\\
{ – 3}\\
2
\end{array}} \right)\) and with length 4 units.CorrectIncorrect - Question 4 of 10
4. Question
Find \(\vec a \bullet \vec b\) if \(\left| {\vec a} \right| = 2,\left| {\vec b} \right| = 4,\theta = 130^\circ \), correcting to two significant figures.
CorrectIncorrectHint
\(\cos \theta = \dfrac{{\vec a \bullet \vec b}}{{\left| {\vec a} \right|\left| {\vec b} \right|}}\)
- Question 5 of 10
5. Question
Find \(k\) given \(\vec a = \left( {\begin{array}{*{20}{c}}
2\\
k
\end{array}} \right)\) and \(\vec b = \left( {\begin{array}{*{20}{c}}
5\\
1
\end{array}} \right)\) are perpendicular.CorrectIncorrectHint
\(\cos \theta = \dfrac{{\vec a \bullet \vec b}}{{\left| {\vec a} \right|\left| {\vec b} \right|}}\)
- Question 6 of 10
6. Question
Find a line parallel to \( – \vec i + 4\vec j\) which cuts the \(x\)-axis at 3 using a Cartesian equation.
CorrectIncorrect - Question 7 of 10
7. Question
Find the coordinates \(\left( {a,b,c} \right)\) of the point where the line with parametric equations \(x = – 2 + 2t,{\rm{ }}y = – 3 – 3t\) and \(z = -4 + 2t\) meets the \(YOZ\) plane.
\(a = \) , \(b = \) , \(c = \)
CorrectIncorrect - Question 8 of 10
8. Question
Find the acute angle, correcting to the nearest degree, between the lines: \(x + 2y = 4\) and \(2x – y = 3\).
degree(s)
CorrectIncorrectHint
\(\cos \theta = \dfrac{{\left| {\vec a \bullet \vec b} \right|}}{{\left| {\vec a} \right|\left| {\vec b} \right|}}\)
- Question 9 of 10
9. Question
Find the acute angle, correcting to the nearest degree, between the lines: \(x + 2y = 4\) and \(x = – 2y + 3\).
degree(s)
CorrectIncorrectHint
\(\cos \theta = \dfrac{{\left| {\vec a \bullet \vec b} \right|}}{{\left| {\vec a} \right|\left| {\vec b} \right|}}\)
- Question 10 of 10
10. Question
A line has a vector equation \(\left( {\begin{array}{*{20}{c}}
x\\
y
\end{array}} \right) = \left( {\begin{array}{*{20}{c}}
3\\
6
\end{array}} \right) + t\left( {\begin{array}{*{20}{c}}
5\\
{ – 4}
\end{array}} \right)\). Find the shortest distance from \(P\left( {2,3} \right)\) to the line, correcting to three significant figures.CorrectIncorrect