
Are you ready to take your first step toward achieving your goal?
- 10 diagnosis quiz questions
- 10 minutes in duration
- Required to attempt all questions
- A mixture of short answer and multiple-choice questions
- Instant feedback straight after the test
OK, let’s get started now!

Are you ready to take your first step toward achieving your goal?
- Ten diagnosis quiz questions
- Ten minutes in duration
- Required to attempt all questions
- A mixture of short-answer and multiple-choice questions
- Instant feedback straight after the quiz
OK, let’s get started now!
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- Question 1 of 10
1. Question
Find the lowest common multiple of 12 and 16.
CorrectIncorrect - Question 2 of 10
2. Question
Ben drove from Town A to Town B, a distance of \( 60 \) km, at an average speed of \( 80 \) km/h. He cycled back at an average speed of \( 20 \) km/h. Find his average speed for the whole journey.
Note that it is not \( \textit{50} \) km/h.Answer: km/h
CorrectIncorrect - Question 3 of 10
3. Question
Calculate the compounded value of investment:
$7200 for 9 months at 6% per annum with interest compounded quarterly.$ , correcting to the nearest cent
CorrectIncorrect - Question 4 of 10
4. Question
Find \(A \) and \(B \), if \(\dfrac{{x + 3}}{{x + 2}} – \dfrac{{x – 4}}{{x – 1}} = \dfrac{{Ax + B}}{{\left( {x + 2} \right)\left( {x – 1} \right)}}\) in its simplest form of a fraction.
\(A \) , \(B \)
CorrectIncorrect - Question 5 of 10
5. Question
Find the maximum \(y\)-value given \(y = – 2{x^2} + 8x + 10\) for \(3 \le x \le 5\).
CorrectIncorrect - Question 6 of 10
6. Question
The equation of a straight line perpendicular to \(y = – \dfrac{x}{2} + 4\) and passing through \(\left( {3,1} \right)\) is \(y = Ax + B\).
\(A = \) , \(B = \)
CorrectIncorrect - Question 7 of 10
7. Question
Solve \(\cos x = \dfrac{1}{2}\) for \(-360^\circ \le x \le 360^\circ \). Write four answers in ascending order.
\(x = \) \(^\circ\), \(^\circ\), \(^\circ\), \(^\circ\),
CorrectIncorrect - Question 8 of 10
8. Question
Find scalars \(a\), \(b\) and \(c\), if \(a\left( {\begin{array}{*{20}{c}}
1\\
0\\
3
\end{array}} \right) + b\left( {\begin{array}{*{20}{c}}
0\\
4\\
6
\end{array}} \right) + c\left( {\begin{array}{*{20}{c}}
3\\
6\\
0
\end{array}} \right) = \left( {\begin{array}{*{20}{c}}
{ – 2}\\
2\\
{15}
\end{array}} \right)\).\(a = \) , \(b = \) , \(c = \)
CorrectIncorrect - Question 9 of 10
9. Question
Find the probability that a randomly chosen student plays tennis known that he plays rugby.
CorrectIncorrect - Question 10 of 10
10. Question
Find the interquartile range of the data represented in the box-and-whisker plot.
\( \begin{array}{c|cccccc}
1 & 1 & 2 &&&& \\
2 & 2 & 5 & 6 & 9 && \\
3 & 0 & 2 & 3 &&& \\
4 & 1 & 4 &&&& \\
\end{array} \)List the scores in ascending order.
The upper quartile is .
The lower quartile is .
The interquartile range is .
CorrectIncorrectHint
Interquartile Range = Upper Quartile – Lower Quartile