Use the quadratic formula find \(A\), \(B\) and \(C\) if the solutions of \({\left( {x – 2} \right)^2} = 1 + x\) are \(\dfrac{{A \pm \sqrt B }}{C}\) in its simplest form.

\(A = \) , \(B = \) , \(C = \)

Correct

Incorrect

Hint

\(\begin{align} \displaystyle a{x^2} + bx + c &= 0\\ x &= \dfrac{{ – b \pm \sqrt {{b^2} – 4ac} }}{{2a}} \end{align}\)

Question 4 of 10

4. Question

Find \(x\), if \(x + 1,x + 2\) and \(x + 3\) are forming right-angled triangle.

\(x\) =

Correct

Incorrect

Question 5 of 10

5. Question

Solve the following simultaneous equations by elimination.

The gradient of a line is \(-1\) and the line passes through the points $\left( {4,2} \right)$ and $\left( {a, – 3} \right)$. Find the value of \(a \).

\(a = \)

Correct

Incorrect

Question 10 of 10

10. Question

The perpendicular bisector of \(\left( {2,4} \right)\) and \(\left( {8,4} \right)\) is \(x + Ay + B = 0\).