Use the quadratic formula find \(A\), \(B\) and \(C\) if the solutions of \({\left( {x – 2} \right)^2} = 1 + x\) are \(\dfrac{{A \pm \sqrt B }}{C}\) in its simplest form.
\(A = \) , \(B = \) , \(C = \)
Correct
Incorrect
Hint
\(\begin{align} \displaystyle a{x^2} + bx + c &= 0\\ x &= \dfrac{{ – b \pm \sqrt {{b^2} – 4ac} }}{{2a}} \end{align}\)
Question 4 of 10
4. Question
Find \(x\), if \(x + 1,x + 2\) and \(x + 3\) are forming right-angled triangle.
\(x\) =
Correct
Incorrect
Question 5 of 10
5. Question
Solve the following simultaneous equations by elimination.
The gradient of a line is \(-1\) and the line passes through the points $\left( {4,2} \right)$ and $\left( {a, – 3} \right)$. Find the value of \(a \).
\(a = \)
Correct
Incorrect
Question 10 of 10
10. Question
The perpendicular bisector of \(\left( {2,4} \right)\) and \(\left( {8,4} \right)\) is \(x + Ay + B = 0\).
